In DataWeave 1.0, with output application/xml, the payload { "fname": "John", "lname": "Doe" } is produced. What is the result?

In DataWeave 1.0, with output application/xml, the payload { "fname": "John", "lname": "Doe" } is produced. What is the result?

• A. An exception - XML wants a key-value pair at the root; it should be user: { fname: payload.firstname, lname: payload.lastname }
• B. XML output will be a root element named John
• C. XML output will be a root element named fname
• D. XML output will be a JSON string inside an XML tag

Answer: (A)

DataWeave 1.0 XML output must have a single root element. The payload you’re starting with is a plain object with two top-level fields, so there’s no root element name to create well-formed XML from. That’s why you’d get an exception unless you wrap the data in a root element, such as user, with fname and lname inside. For example, wrapping yields XML like <user><fname>John</fname><lname>Doe</lname></user>. The other ideas—having a root named John or fname, or placing a JSON string inside an XML tag—don’t produce well-formed XML from a bare map. Wrapping into a root element is the correct approach.

DataWeave 1.0 XML output must have a single root element. The payload you’re starting with is a plain object with two top-level fields, so there’s no root element name to create well-formed XML from. That’s why you’d get an exception unless you wrap the data in a root element, such as user, with fname and lname inside. For example, wrapping yields XML like JohnDoe. The other ideas—having a root named John or fname, or placing a JSON string inside an XML tag—don’t produce well-formed XML from a bare map. Wrapping into a root element is the correct approach.